Precalculus Textbook 8th Edition Section 1.4 Exercise 49 Solution

Precalculus Textbook 8th Edition Section 1.4 Exercise 49 Solution

Question:

If f(x) = x2 + 1, then find fof(x).

Option A: 2x2 + 2

Option B: 2x2 + 1

Option C: x4 + 1

Option D: x4 + 2x2 + 1

Option E: x4 + 2x2 + 2

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Solution:

The given function is f(x) = x2 + 1.

Then, fof(x) = [f(x)]2 + 1 =(x2 + 1)2 + 1 = x4 + 2x2 + 1 + 1 = x4 + 2x2 + 2 (Option E)

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